A Difficult Riddle

[Eminem]

I just solved this problem, which took me about an hour to figure out. It's not really a riddle but since there's no better way to explain it, it will be called a riddle. Anyone who can solve it will get a lot of rep points.


There are 13 pennies on the desk. They are all in one group, 5 of them being heads and 8 being tales. You have to split them into 2 groups with the same amount of heads in both groups (you can flip the coins). The trick is, you have to do it in the dark, not knowing which coins are which.

[fatpimp]

what do you mean by, "you can flip the coins"

[MGselwonK]

i would be surprised and delighted if there was a logical answer to this


my answer is going to be "flashlight" or "pick which ones are head by feeling them"

[Eminem]

i mean... that IF you could see them, there would be 5 heads and 8 tails. so by flipping a tail over, you will get 6 heads, then just put 3 heads in one group and 3 in the other.but you cant see them, you cant feel them, because they all feel the same. there is a perfectly logical answer to this, and trust me its hard to figure out

[THEoneFEEM]

I just solved this problem, which took me about an hour to figure out. It's not really a riddle but since there's no better way to explain it, it will be called a riddle. Anyone who can solve it will get a lot of rep points.


There are 13 pennies on the desk. They are all in one group, 5 of them being heads and 8 being tales. You have to split them into 2 groups with the same amount of heads in both groups (you can flip the coins). The trick is, you have to do it in the dark, not knowing which coins are which.

wouldn't you jsut split the coins into two groups, thne fLip one coin. it doesn't matter wihce because if you:

A) flip a heads it will be tails, then there will be 2heads in each group
b) if you flip a tail it will be head, thus being 3 heads in each group

just a quick guess...i will try to actually solve it later...hehe
__________________________________________________ ______
yeah i realized this after posted, but i was jsut a quick guess...i didn't even spend a minute thinking about it. i will solve it later... after my killer headache...nice riddle....will you post the answer later?

[ribwich]

wouldn't you jsut split the coins into two groups, thne fLip one coin. it doesn't matter wihce because if you:

A) flip a heads it will be tails, then there will be 2heads in each group
b) if you flip a tail it will be head, thus being 3 heads in each group

just a quick guess...i will try to actually solve it later...hehe

I was thinking the same thing but realized the problem. Unless you're allowed to see the coins before splitting them into groups, there's no guarantee you'll get 3 heads in one group and two heads in the other group. You could get all five heads in one of the groups.

[Mainer]

just feel the ones that your not sure what they are

[Eminem]

I was thinking the same thing but realized the problem. Unless you're allowed to see the coins before splitting them into groups, there's no guarantee you'll get 3 heads in one group and two heads in the other group. You could get all five heads in one of the groups.


thats correct, there in lies the problem. and you're not allowed to "feel" them mainer, ive already said that


btw, if you think you've got it, PM me first. i dont want to give it away that fast. i will give the answer if its not solved in a few pages of posts.

[Big D]

Somehow, I think that every penny should be flipped...leaving 8 heads and 5 tails...but that still doesn't solve how to then get the pennies into groups with 4 heads each...

Edit: When you say two groups, does that mean a group of 6 and a group of 7? Do all the pennies have to be in the 2 groups...or could I have two groups of 4 with extras on the side?

[Eminem]

Somehow, I think that every penny should be flipped...leaving 8 heads and 5 tails...but that still doesn't solve how to then get the pennies into groups with 4 heads each...

Edit: When you say two groups, does that mean a group of 6 and a group of 7? Do all the pennies have to be in the 2 groups...or could I have two groups of 4 with extras on the side?


all the pennies have to be in 2 groups... but the groups could be 1 and 12, providing that you can prove that there are the same amount of heads.

[Bigheaded Chief]

btw, if you think you've got it, PM me first. i dont want to give it away that fast. i will give the answer if its not solved in a few pages of posts. looks like we got time to waste
maybe putting one on its side will help so there are 12 pennies posible

[Chewy]

I give what is it?? :rolleyes:

[Chewy]

ok enough post the answer!!! I need to sleep tonight.... Grrrrr :mad:

[MGselwonK]

i dont think there is an answer, i honestly dont

[Chewy]

I want the answer!!!!!!!!!!! :mad: :mad: :mad: :mad:

[deagle crazy]

i want the answer to!!! and if u dont wanna post the answer u can pm it to me :D

[Big D]

Finally!!! I solved the damn riddle, but out of respect for em, I'm not going to post the answer yet per his request. I pm'd the answer to him, and I'll let him post the answer for everyone else when he wants to.

Feel free to pm me if you want the answer...as long as you won't turn around and post it afterward.

[Eminem]

Big D won, he got the correct answer. I have no idea how long it took him, but congratulation anyways. If you guys are giving up PM me for the answer but you have to promise not to post it here later.

[MGselwonK]

are you an idiot? post the damn answer already


there is nobody saying "WAIT DONT POST THE ANSWER I HAVENT SOLVED IT YET" its fucking obvious that everybody who is going to look at this thread has gotten the answer or given up already

[DreamTheater]

are you an idiot? post the damn answer already


there is nobody saying "WAIT DONT POST THE ANSWER I HAVENT SOLVED IT YET" its fucking obvious that everybody who is going to look at this thread has gotten the answer or given up already

i must agree. give us the answer or give us death..preferably not death.

[Eminem]

are you an idiot? post the damn answer already


there is nobody saying "WAIT DONT POST THE ANSWER I HAVENT SOLVED IT YET" its fucking obvious that everybody who is going to look at this thread has gotten the answer or given up already


no i am not an idiot, i just dont want to ruin it for those who still want to try and solve it. however, since everyone feels so eager to know the solution:



I take 5 pennies from the group of 13, and flip all of them.

If I grabbed all 5 heads, then they become tails, abd the groups are even at 0 apiece. If I grabbed 5 tails, then they all become heads, and they are all even at 5 heads apiece. This as also true for any combination of heads and tails...


(exactly how D wrote it)

[Devastation]

Or you could just put the pennies in your pocket and become 13 cents richer.

[borlosky]

you wouldn't be able to split them evenly, there's 13 pennies,, you'd have 6 of one, and 7 of the other

[borlosky]

you wouldn't be able to split them evenly, there's 13 pennies,, you'd have 6 of one, and 7 of the other


hahahaha, nevermind, i'm retarded, i read it wrong......it's been a LOOOOOOONG ass day at work :(